ads2_2022/code/python/src/algorithms/euklid/algorithms.py

98 lines
3.0 KiB
Python

#!/usr/bin/env python3
# -*- coding: utf-8 -*-
# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
# IMPORTS
# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
from src.thirdparty.types import *;
from src.thirdparty.maths import *;
from models.generated.config import *;
from src.core.utils import *;
from src.models.euklid import *;
from src.algorithms.euklid.display import *;
# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
# EXPORTS
# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
__all__ = [
'euklidean_algorithm',
];
# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
# METHOD euklidean algorithm
# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
def euklidean_algorithm(
a: int,
b: int,
verbose: bool = False,
) -> Tuple[int, int, int]:
'''
Führt den Euklideschen Algorithmus aus, um den größten gemeinsamen Teiler (ggT, en: gcd)
von zwei positiven Zahlen zu berechnen.
'''
################
# NOTE:
# Lemma: gcd(a,b) = gcd(mod(a, b), b)
# Darum immer weiter (a, b) durch (b, gcd(a,b)) ersetzen, bis b == 0.
################
steps = [];
d = 0;
while True:
if b == 0:
d = a;
steps.append(Step(a=a, b=b, gcd=d, div=0, rem=a, coeff_a=1, coeff_b=0));
break;
else:
# Berechne k, r so dass a = k·b + r mit k ≥ 0, 0 ≤ r < b:
r = a % b;
k = math.floor(a / b);
# Speichere Berechnungen:
steps.append(Step(a=a, b=b, gcd=0, div=k, rem=r, coeff_a=0, coeff_b=0));
# ersetze a, b durch b, r:
a = b;
b = r;
################
# NOTE:
# In jedem step gilt
# a = k·b + r
# und im folgenden gilt:
# d = coeff_a'·a' + coeff_b'·b'
# wobei
# a' = b
# b' = r
# Darum:
# d = coeff_a'·b + coeff_b'·(a - k·b)
# = coeff_b'·a + (coeff_a' - k·coeff_b)·b
# Darum:
# coeff_a = coeff_b'
# coeff_b = coeff_a' - k·coeff_b
################
coeff_a = 1;
coeff_b = 0;
for step in steps[::-1][1:]:
(coeff_a, coeff_b) = (coeff_b, coeff_a - step.div * coeff_b);
step.coeff_a = coeff_a;
step.coeff_b = coeff_b;
step.gcd = d;
if verbose:
step = steps[0];
repr = display_table(steps=steps, reverse=True);
expr = display_sum(step=step);
print('');
print('\x1b[1mEuklidescher Algorithmus\x1b[0m');
print('');
print(repr);
print('');
print('\x1b[1mLösung\x1b[0m');
print('');
print(f'a=\x1b[1m{step.a}\x1b[0m; b=\x1b[1m{step.b}\x1b[0m; d = \x1b[1m{step.gcd}\x1b[0m = {expr}.');
print('');
return d, coeff_a, coeff_b;