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master > master: 10.1 (b) Übertragungsfehler

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RD 2021-01-28 15:10:30 +01:00
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@ -6482,13 +6482,13 @@ Das Hauptziel hier ist, eine Variant anzubieten, gegen die man seine Versuche ve
&\psi(\sum_{i=1}^{d}c_{i}w_{i})=\zerovector\\ &\psi(\sum_{i=1}^{d}c_{i}w_{i})=\zerovector\\
&&\text{wegen Linearität von $\psi$}\\ &&\text{wegen Linearität von $\psi$}\\
&\Longrightarrow &\Longrightarrow
&\sum_{i=1}^{d}c_{i}w_{i}\in\ker(\psi)=\{\zerovector\}\\ &\sum_{i=1}^{d}c_{i}w_{i}\in\ker(\psi)\\
&&\text{wegen \uline{Injektivität} von $\psi$ + \cite[Lemma~6.1.4]{sinn2020}}\\
&\Longrightarrow &\Longrightarrow
&\sum_{i=1}^{d}c_{i}w_{i}=\zerovector\\ &\sum_{i=1}^{d}c_{i}w_{i}=\zerovector\\
&&\text{wegen \uline{Injektivität} von $\psi$ + \cite[Lemma~6.1.4]{sinn2020}}\\
&\Longrightarrow &\Longrightarrow
&c_{1},c_{2},\ldots,c_{d}=0_{K}\\ &c_{1},c_{2},\ldots,c_{d}=0_{K}\\
&&\text{weil ${(x_{1},x_{2},\ldots,x_{d})}$ linear unabhängig ist.}\\ &&\text{weil ${(w_{1},w_{2},\ldots,w_{d})}$ linear unabhängig ist.}\\
\end{longmathe} \end{longmathe}
Damit gilt Damit gilt