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RD 2020-12-02 10:32:03 +01:00
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docs/loesungen.pdf

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docs/loesungen.tex

@ -5504,12 +5504,12 @@ Insbesondere sind die o.\,s. definierten Operationen assoziativ.
Darum existieren multiplikative Inverse, $x^{-1},y^{-1}\in K$. Darum existieren multiplikative Inverse, $x^{-1},y^{-1}\in K$.
Aus $xy=0$ folgt dann Aus $xy=0$ folgt dann
\begin{mathe}[mc]{rcl} \begin{mathe}[mc]{rcccccccccccl}
1 &= &y^{-1}y\\ 1 &= &y^{-1}y
&= &y^{-1}1y\\ &= &y^{-1}1y
&= &y^{-1}(x^{-1}x)y\\ &= &y^{-1}(x^{-1}x)y
&= &(y^{-1}x^{-1})(xy)\\ &= &(y^{-1}x^{-1})(xy)
&= &(y^{-1}x^{-1})0\\ &= &(y^{-1}x^{-1})0
&= &0.\\ &= &0.\\
\end{mathe} \end{mathe}